Modify resource structure fails

Question

I received the following error when attempting to save changes to Resource Structure in Resource Manager. I was trying to add an existing resource to the structure of another resource. Anyone seen it before or know how to fix?

===================================


Unhandled exception occurred (QualiSystems.Infrastructure.Common)


------------------------------
Program Location:


   at QualiSystems.Infrastructure.Common.ExceptionHandling.ExceptionHandler.EmptyExceptionHandler.Handle(Exception e)
   at QualiSystems.Infrastructure.Common.ExceptionHandling.ExceptionHandler.CompositeExceptionHandler.Handle(Exception e)
   at QualiSystems.ResourceManagement.Client.Logic.ResourceStructure.ResourceStructureEditor.OnCommit()
   at QualiSystems.Infrastructure.DataModel.EditManager.BaseEditor.OnCommit(CommitResult& result)
   at QualiSystems.Infrastructure.DataModel.EditManager.BaseEditor.Commit(CommitResult& result)
   at QualiSystems.Infrastructure.DataModel.EditManager.BaseEditor.Commit()
   at QualiSystems.Infrastructure.DataModel.EditManager.CompositeEditManager.Commit()
   at QualiSystems.ResourceManagement.Client.Application.ResourceStructure.ResourceStructureDocumentPresenter.DocumentSaveRequsted(Object sender, EventArgs e)
   at QualiSystems.Infrastructure.Application.Documents.Document.Save()
   at QualiSystems.Infrastructure.Application.Commands.SaveDocumentCommandBase.SaveSingleDocument(IDocument document, IUserInterfaceService userInterfaceService, IUndoManager undoManager)
   at QualiSystems.Infrastructure.Application.Commands.SaveDocumentCommandBase.SaveDocuments(IEnumerable`1 documents, IUserInterfaceService userInterfaceService)
   at QualiSystems.Infrastructure.Application.Commands.SaveActiveDocumentCommand.ExecuteInternal()
   at QualiSystems.Infrastructure.Application.Commands.SaveDocumentCommandBase.Execute()
   at QualiSystems.Infrastructure.Presentation.Desktop.CommandErrorHandler.Execute()
   at QualiSystems.Infrastructure.Presentation.Desktop.DesktopManager.HandleInputTrigger(Object sender, InputEventArgs e, ISelection selection)
   at QualiSystems.Infrastructure.Presentation.Desktop.Desktop.KeyTriggerListener.ControlOnKeyDown(Object sender, KeyEventArgs e)
   at System.Windows.Input.KeyEventArgs.InvokeEventHandler(Delegate genericHandler, Object genericTarget)
   at System.Windows.RoutedEventArgs.InvokeHandler(Delegate handler, Object target)
   at System.Windows.RoutedEventHandlerInfo.InvokeHandler(Object target, RoutedEventArgs routedEventArgs)
   at System.Windows.EventRoute.InvokeHandlersImpl(Object source, RoutedEventArgs args, Boolean reRaised)
   at System.Windows.UIElement.RaiseEventImpl(DependencyObject sender, RoutedEventArgs args)
   at System.Windows.UIElement.RaiseTrustedEvent(RoutedEventArgs args)
   at System.Windows.UIElement.RaiseEvent(RoutedEventArgs args, Boolean trusted)
   at System.Windows.Input.InputManager.ProcessStagingArea()
   at System.Windows.Input.InputManager.ProcessInput(InputEventArgs input)
   at System.Windows.Input.InputProviderSite.ReportInput(InputReport inputReport)
   at System.Windows.Interop.HwndKeyboardInputProvider.ReportInput(IntPtr hwnd, InputMode mode, Int32 timestamp, RawKeyboardActions actions, Int32 scanCode, Boolean isExtendedKey, Boolean isSystemKey, Int32 virtualKey)
   at System.Windows.Interop.HwndKeyboardInputProvider.ProcessKeyAction(MSG& msg, Boolean& handled)
   at System.Windows.Interop.HwndSource.CriticalTranslateAccelerator(MSG& msg, ModifierKeys modifiers)
   at System.Windows.Interop.HwndSource.OnPreprocessMessage(Object param)
   at System.Windows.Threading.ExceptionWrapper.InternalRealCall(Delegate callback, Object args, Int32 numArgs)
   at System.Windows.Threading.ExceptionWrapper.TryCatchWhen(Object source, Delegate callback, Object args, Int32 numArgs, Delegate catchHandler)

Thank you,

Answer 1

Best Answer

Answer by Yaniv.K · Oct 11, 2017 at 08:37 PM

Hi @babrams,

I see that you also opened a ticket in the support portal, I think it such exceptions should be handled from there anyway.

FYI, regarding this screen (resource structure) - you can't assign a model to be a child of another model, if you already have root resources from that model (ViasatBroadbandModem in this case). When that's the case, you're supposed to get a proper error message saying that, like this:

Error updating structure.
Cannot add relation OnPATH Switch 3912->DemoAutoLoad:
Root resource named 'DemoAutoLoad1' of model 'DemoAutoLoad' is defined.

Yaniv

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Answer 2

Answer by babrams · Oct 11, 2017 at 08:46 PM

HI Yaniv,

Thanks for the reply. To clarify: are you saying that I should not be able to create this resource model relationship because I have existing resource instances created from the ViasatBroadbandModem template?

If that's true, I still need a solution to this problem: I need to create a modem shelf resource model that is meant to contains 8 or 16 ViaSatBroadbandModems. How do I proceed?

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Yaniv.K ♦♦ · Oct 11, 2017 at 08:56 PM 0

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Yes, you can't have such structure.

Regarding your use case, if you want, we can have a short call and discuss it. But in general, you'll need to have 2 different models for this. One that will be used for root-resources and one that will be used for sub-resources. The limitation will be that you won't be able to "move" a resource from being a sub-resource to be a root-resource or vice-versa.

Yaniv

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Modify resource structure fails

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